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Q.

Four identical discs each of mass M and diameter 'a' are arranged in a small plane as shown in figure. If the moment of inertia of the system about OO is x4Ma2. Then the value of x will be

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answer is 3.

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Detailed Solution

I1=I4=MR24

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I2=I3=54MR2

I=I1+I2+I3+I4

I=12MR24

Given diameter =a=2R⇒R=a/2

Isys=3Ma24

Isys=3Ma24

Given I=x4Ma2⇒x=3

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