Four light sources produce the following waves
(i) $y_1=a\sin \left(\omega t+{\varphi }_1\right)$
(ii) ${\mathrm{y}}_2=\mathrm{asin}\left(2\mathrm{\omega t}\right)$
(iii) ${\mathrm{y}}_3={\mathrm{a}}^{\mathrm{\prime }}\sin \left(\mathrm{\omega t}+{\mathrm{\varphi }}_2\right)$
(iv) ${\mathrm{y}}_4={\mathrm{a}}^{\mathrm{\prime }}\sin (3\mathrm{\omega t}+\mathrm{\varphi })$
Superposition of which two waves gives rise to interference

Light waves having same frequency and constant phase difference (coherent) produces the interference pattern. Light sources (i) and (iii) has same frequency, hence they can produce interference.