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Q.

Four moles of a perfect gas heated to increase its temperature by 2°C absorbs heat of 40 cal at constant volume. If the same gas is heated at constant pressure the amount of heat supplied is, (R=2 cal/mol K)

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a

94 cal

b

28 cal

c

56 cal

d

84 cal

answer is B.

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Detailed Solution

detailed_solution_thumbnail

ΔQv=du=ncvΔT⇒40=4×cv×2

∴cv=5cal/molK

∴cp−cv=R

∴cp=cv+R

∴cp=5+2=7cal/molK

ΔQp=ncpΔT=4×7×2=56cal

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