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Four moles of electrons were transferred from anode to cathode in an experiment on electrolysis of water. The total volume of the two gases (dry and at STP) produced will be approximately (in litres)

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89.4

22.4

44.8

67.2

answer is C.

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Detailed Solution

$2 H_{2} O \overset{4 e^{-}}{\to} 2 H_{2} + O_{2}$

For 4 moles of electrons total 3 moles of gaseous mixture is liberated

volume liberated at STP = 3 $\times$ 22.4 =67.2 lits

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