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Q.

Four numbers are chosen at random from ${1, 2, 3, ...50} .$ the probability that they are not side by side numbers is

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a

$\frac{4899}{4900}$

b

$1 - \frac{47}{^{50} C_{4}}$

c

$\frac{1}{4900}$

d

$\frac{4^{2}}{^{52} c_{2}}$

answer is B, C.

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Detailed Solution

Combination of 4 number’s from 50

They are consecutive $=$

Question Image

$= 47$

$P (E) = \frac{^{50} C_{4} - 47}{^{50} C_{4}} = 1 - \frac{47}{^{50} C_{4}}$

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Four numbers are chosen at random from {1, 2, 3, ...50}. the probability that they are not side by side numbers is