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Four particles each of mass 1 kg are at the four corners of a square of side 1m. The M.I of the system about a normal axis through centre of square is

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a

2.5 {kgm}^{2}

b

1.2 {kgm}^{2}

c

6 {kgm}^{2}

d

2 {kgm}^{2}

answer is C.

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Detailed Solution

I = 4 {mr}^{2}

$= 4 \times 1 \times {(\frac{1}{\sqrt{2}})}^{2}$

$I = 2 {kgm}^{2}$

(or)

Question Image

$I = {mr}^{2}$

here $r = \frac{1}{\sqrt{2}}$

$∴ I_{square} = 4 ({mr}^{2})$

$\Rightarrow 4 \times 1 \times {(\frac{1}{\sqrt{2}})}^{2} = 4 \times 1 \times \frac{1}{2}$

$\Rightarrow 2 {kgm}^{2}$

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Four particles each of mass 1 kg are at the four corners of a square of side 1m. The M.I of the system about a normal axis through centre of square is