Q.

Four point charge of +107C,107C,2×107C and+2×107C are placed respectively at the corners A, B, C, D of a 0.05m square. Find the magnitude of the resultant force on the charge at D.

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a

0.2 dyne

b

0.02 newton

c

0.2 newton

d

2 dyne

answer is B.

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Detailed Solution

Question Image

F=14πε0q1q2r2

FAD=K2×10-140.052

FBD=K2×10-140.052×2

FCD=K4×10-140.052

on substituting the values resultant will be 0.2N.

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