Four point masses are placed at four corners of a square as shown. When positions of m and 2m are interchanged,

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gravitational field strength at centre will increase

gravitational field strength at centre will decrease

gravitational potential at centre will remain unchanged

gravitational potential at centre wiII decrease

answer is A, C.

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Detailed Solution

$E = \frac{G m}{r^{2}}$

$E'_{n e t} = 2 \sqrt{2} E = \frac{2 \sqrt{2} G m}{r^{2}} E'_{n e t} = \sqrt{{(9 E)}^{2} + E^{2}} = \sqrt{10} E = \frac{\sqrt{10} G m}{r^{2}} E'_{n e t} > E_{n e t}$

Potential in both cases is

$V_{n e t} = - \frac{G}{r} (m + 2 m + 3 m + 4 m) = - \frac{10 G m}{r}$

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