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Q.

Four Resistances P,Q,R,X formed a wheat stone bridge. The bridge is balanced when $R = 100 Ω$ . If P and Q are inter changed the bridge balance $121 Ω$ for. The value of x is

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a

$200 Ω$

b

$100 Ω$

c

$300 Ω$

d

$110 Ω$

answer is D.

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Detailed Solution

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Case 1: $\frac{P}{Q} = \frac{R}{X} \Rightarrow \frac{P}{Q} = \frac{100}{X} \dots 1$

Case 2: $\frac{Q}{P} = \frac{121}{X} \dots 2$

$\Rightarrow \frac{X}{121} = \frac{100}{X}$

$X^{2} = 100 \times 121 \Rightarrow X = 110 Ω$

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