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Q.

Four resistors of $100 Ω$ each are connected in the form of a square. The effective resistance along the diagonal is

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a

300 Ω

b

200 Ω

c

100 Ω

d

400 Ω

answer is D.

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Detailed Solution

{Rs}_{1} = R_{1} + R_{2} = 100 + 100 = 200 Ω

${Rs}_{2} = R_{3} + R_{4} = 100 + 100 = 200 Ω$

$\frac{1}{R_{p}} = \frac{1}{{Rs}_{1}} + \frac{1}{{Rs}_{2}} = \frac{1}{200} + \frac{1}{200} = \frac{2}{200} = \frac{1}{100}$

$\frac{1}{R_{p}} = \frac{1}{100}$

$R_{p} = 100 Ω$

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Four resistors of 100 Ω each are connected in the form of a square. The effective resistance along the diagonal is