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Q.

Four uniform wires having equal length 1m each and resistance in the ratio 1:2:3:4  are connected together to form a square CDEF in that order i.e. CD, DE, EF, FC and resistance of wire CD is ‘r’. This loop surrounds a cylindrical region of circular cross section in which uniform magnetic field whose net flux depends on time according to relation  ϕ=40t  weber, where‘t’ is in second. The magnetic field is perpendicular to the plane of square loop. Centre of circular cross section and square loop coincides. (V1&V2 are ideal voltmeters, magnetic field is confined to a cylindrical region and its axis coincides with that of square)

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a

The potential difference between point C and F is 6 volt

b

Reading of voltmeter  V2 is 16 volt 

c

Reading of voltmeter  V1 is 8 volt 

d

Reading of voltmeters V1&V2  are equal 

answer is B, D.

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Detailed Solution

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ε=dφdt=40V i=ε10r=4010r=4r V1=2r×i V2=8r×i

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