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. Fourty electric bulbs are connected in series across a 220 V supply. After one bulb is fused the remaining 39 are connected again in series across the same supply. The illumination will be

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more with 40 bulbs than

more with 39 bulbs than with 40

equal in both the cases

in the ratio $40^{2} : 39^{2}$

answer is B.

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Detailed Solution

Since, the voltage is same for the two combinations, therefore $p \propto \frac{1}{R} .$ Hence, the combination of39 bulbs will glow more.

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