Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

f:RR  fx2+x+3+2fx23x+5=6x210x+17 xR then the value of f(100) is 

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

b

c

d

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

 obviously f is a linear polynomial    (Since degree of LHS and RHS is same)

letf(x)=ax+b hence fx2+x+3+2fx23x+56x210x+17ax2+x+3+b+2ax23x+5+b6x210x+17comparing coeff of x2 and coeff. of x a+2a=6......(1) a6a=10......(2)   a=2comparing constants 3a+b+10a+2b=17 6+b+20+2b=17 b=3 f(x)=2x3f(100)=197

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring