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Q.

Freezing point of an aqueous solution  is — 0.186°C. If the values of Kb, and Kf, of water are respectively 0.52 K kg mol1 and 1.86Kkgmol1then the elevation of boiling point of the solution in K is 

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a

0.52 

b

1.04

c

1.34

d

0.052

answer is D.

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Detailed Solution

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ΔTf=ikfm;ΔTb=ikbm ΔTfΔTb=kfkb ΔTf=00.186C=0.186C 0.186ΔTb=1.860.52ΔTb=0.52×0.1861.86=0.052

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