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Q.

Freezing point of sucrose solution is -0.1860 C. Boiling point of the same solution will be (Kb and Kf of water are 0.52 K kg mol-1 and 1.86 K kg mol-1)

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a

373.52 K

b

373.104 K

c

374.04 K

d

373.052 K

answer is B.

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Detailed Solution

∆Tf∆Tb=KfKb; 0.186∆Tb=1.860.52; ∆Tb=0.052 K; Tb=373.052 K;

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