Freundlich isotherm explain the variation of extent of physical adsorption with pressure. A graph is plotted between $\log \frac{x}{m} (y - axis)$ vs log P(x – axis) value of slope of the graph cannot be (x = mass of adsorbate, m = mass of adsorbent)

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1.2

0.45

0.2

0.33

answer is A.

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Detailed Solution

Freundlich isotherm
$\begin{array}{l} \frac{x}{m} = {KP}^{\frac{1}{n}} \\ \log \frac{x}{m} = \log K + \frac{1}{n} \log P \end{array}$
Slope $= \frac{1}{n} (\frac{1}{n} ranges from 0 to 1)$

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