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Q.

From 392 mg of $H_{2} {SO}_{4}, 1.204 \times 10^{21}$ molecules of $H_{2} {SO}_{4}$ are removed. How many moles of $H_{2} {SO}_{4}$ are left?

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a

$2 \times 10^{- 3}$

b

$1.2 \times 10^{- 3}$

c

$4 \times 10^{- 3}$

d

$1.5 \times 10^{- 3}$

answer is A.

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Detailed Solution

The moles left;

$n_{left} = \frac{392 \times 10^{- 8}}{98} - \frac{1 .204 \times 10^{21}}{6 .023 \times 10^{23}}$

$n_{left} = 2 \times 10^{- 3}$

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