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Q.

From a circular disc of radius R and mass 9M, a small disc of mass M and radius $\frac{R}{3}$ is removed concentrically. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through its centre is :

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a

MR²

b

2MR²

c

$\frac{4}{9} {MR}^{2}$

d

$\frac{40}{9} {MR}^{2}$

answer is .

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Detailed Solution

Use parallel axis theorem

Question Image

$I_{0} = \frac{1}{2} (9 M) R^{2} - \frac{1}{2} (M) {(\frac{R}{3})}^{2} = \frac{40}{9} {MR}^{2}$

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