From a complete ring of mass ‘m’ and radius ‘R’ a 30⁰ sector is removed. The M.I. of the remaining ring about an axis through centre of ring and normal to its plane is

The number 8 particle left in the ring is $\frac{11}{12}$ if an arc producing an angle is moved essentially $\frac{1}{12}$ th of the ring such.
​Thus $\mathrm{I}=\frac{11}{12}{\mathrm{MR}}^2$

Hence the correct answer is $\frac{11}{12}{\mathrm{MR}}^2.$