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From a frequency distribution, c = 3, l = 65.5, f = 42, m = 23, N = 102 then median is (l = lower limit of the median class, m = cumulative frequency of the class preceeding the median class, N = total frequency, f = frequency of the median class, c = width of the median class)

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65.5

67.50

66.93

66.43

answer is B.

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Detailed Solution

Median $l + (\frac{N / 2 - m}{f}) \times c$

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