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Q.

From a frequently distribution, c=3,l=65.5,f=42,m=23,N=102  the median is (1= lower limit of the median class, m= cumulative frequency of the class preceding the median class. N= total frequency, f=  frequency of the median class, c=  width of the median class )

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a

 65.5

b

67.50

c

66.93

d

66.43

answer is B.

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Detailed Solution

Median =L+(N2c.ff)×c=65.5+(512342)3=67.5

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