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From a pack of 52 cards, 3 cards are drawn successively with replacement each time. The probability of getting at least one king is

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$1 - \frac{12^{3}}{13^{3}}$

$\frac{1}{{(13)}^{3}}$

$1 - \frac{1}{13^{3}}$

$\frac{12^{3}}{13^{3}}$

answer is A.

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Detailed Solution

probability of getting king out of 52 cards is $\frac{4}{52} = \frac{1}{13}$

probability of getting no king = $1 - \frac{1}{13} = \frac{12}{13}$ one time

The probability of getting at least one king is=1- probability of getting no kings=1 $- {(\frac{12}{13})}^{3}$

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