From a point charge, there is a fixed point A. At A, there is an electric field of 500 $V/m$ and potential difference of 3000 V. Distance between point charge and A will be

Given: Electric field (E) = 500 $V/m$

and potential difference (V) = 3000 V. 

We know that electric field

$\left(E\right)=500=\frac{V}{d}\text{ or }d=\frac{3000}{500}=6\mathrm{m}$

[ where d = Distance between point charge and A]