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From a point charge there is a fixed point A. At that point there is an electric field of 500 V/m and potential of 3000 V. Then, the distance of point A from the point charge is

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36 m

6 m

144 m

12 m

answer is A.

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Detailed Solution

Potential, V = E $\cdot$ d

$∴$ Distance from the point charge, $d = \frac{V}{E} = \frac{3000}{500} = 6 m$

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