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From a point on the ground at a distance $' a'$ from the foot of a pole, a balls is thrown, at an angle of $45^{0}$ , which just touches the top of pole at P and strikes the ground at a distance of $' b'$ on the other side of it. Find the height of the pole.

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$\frac{a b}{a - b}$

$\frac{a + b}{a b}$

$\frac{a b}{a + b}$

$\frac{a - b}{a b}$

answer is C.

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Detailed Solution

$y = x \tan α (1 - \frac{x}{R}) \begin{array}{l} h = a \tan 45^{0} (1 - \frac{a}{a + b}) \\ = \frac{a b}{a + b} \end{array}$

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