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Q.

From a set of 20 cards numbered from 1 to 20 one is drawn at random. Then the probability of selecting that the number is divisible by 3 or 5 is

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a

$\frac{1}{2}$

b

$\frac{1}{5}$

c

$\frac{9}{20}$

d

$\frac{3}{10}$

answer is C.

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Detailed Solution

Divisible by 3: 3,6,9,12,15,18

Divisible by 5: 5,10,15,20

$n (A) = {}^{9}C_{1} = n (3) + n (5) - n (3 \cap 5)$

$P (A) = \frac{6 + 4 - 1}{20} = \frac{9}{20}$

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