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From an elevated point ‘P’ a stone is projected vertically upwards, when it reaches a distance ‘d’ below ‘p’, its velocity is doubled. The greatest height reached by it above ‘P’ is

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$3 d$

$2 d$

$\frac{d}{3}$

$\frac{d}{2}$

answer is A.

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Detailed Solution

${(2 u)}^{2} - u^{2} = 2 g d$
$3 u^{2} = 2 g d$
$\frac{u^{2}}{2 g} = \frac{d}{3}$

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