From an inclined plane two particles are projected with same speed at same angle $\theta$, one up and other down the plane as shown in figure. Which of the following statement(s) is/are correct?

Component of velocity of projection of each particle perpendicular to the inclined plane =u sin $\theta$

Component of g perpendicular to the inclined plane = g cos$\theta$

Therefore in a direction perpendicular to the inclined plane , 0 = (u sin $\theta$) T - $\frac{1}{2}\left(g \cos \theta \right)T^2 = 0 \Rightarrow T =\frac{2u \sin \theta }{g \cos \theta }$