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Q.

From any point P on the circle x2+y26x8y+15=0 tangents PA, PB are drawn to the circle x2+y26x8y+20=0 and the locus of the orthocentre of the ΔlePAB is a circle then

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a

centre is (3, 4)

b

centre is (–3, 2)

c

radius is 5

d

radius is 10

answer is A, D.

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Detailed Solution

sinθ=510θ=450APB=π/2

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orthocentre of APB is P

locus of P is the bigger circle

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