From the above data the rate law for the equation A+B→ products is equal to

A+B→Products From (i) and (ii) rate =k[A]m [B]n Order with respect to A=2Order with respect to B=1rate=K[A]2[B]1

From the above data the rate law for the equation A+B→ products is equal to

A+B→Products From (i) and (ii) rate =k[A]m [B]n Order with respect to A=2Order with respect to B=1rate=K[A]2[B]1

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From the above data the rate law for the equation $A + B \to$ products is equal to

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$K [A] [B]$

$K [A]^{2} [B]^{2}$

$K [A]^{2} [B]$

$K [A] [B]^{2}$

answer is C.

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Detailed Solution

$A + B \to Products From (i) and (ii) rate = k {[A]}^{m} {[B]}^{n} \begin{aligned} \end{aligned}$

Order with respect to A=2

Order with respect to B=1

$rate = K [A]^{2} [B]^{1}$

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From the above data the rate law for the equation A+B→ products is equal to

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From the above data the rate law for the equation $A + B \to$ products is equal to