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Q.


From the choices, find the sum of the first 15 multiples of 8.

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a

870

b

960

c

690

d

788 

answer is B.

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Detailed Solution

We have to find the sum of the first 15 multiples of 8.
The three-digit numbers that are completely divisible by 13 are:
8, 16, 24, 32, 40,…
The above numbers are in the form of an AP.
So,
a=8,
d=168 =8 ,
n=15
We know that sum of n-terms in AP is,
S n = n 2 [2a+(n1)d]
Substitute the known values in the above formula,
S 15 = 15 2 [2(8)+(151)8)]
= 15 2 [16+112] =960
960 is the sum of the 15 multiples of 8.
Hence option 2) is correct.
 
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From the choices, find the sum of the first 15 multiples of 8.