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From the figure, the angle of depression of point C from the point P is:

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90^{\circ}

60^{\circ}

30^{\circ}

45^{\circ}

answer is C.

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Detailed Solution

In the given figure,

∠ PBA = 60^{o}

∠ PCA = 45^{o}

∠ BPC = 30^{o}

△ PAB

∠ APB + ∠ PAB + ∠ PBA = 180^{\circ}

∠ APB + 90^{\circ} + 60^{\circ} = 180^{\circ}

∠ APB = 30^{\circ}

Now,

∠ APC = ∠ APB + ∠ BPC

∠ APC = 30^{\circ} + 30^{\circ}

∠ APC = 60^{\circ}

Similarly, in

△ PAC

90^{\circ} + 60^{\circ} + ∠ PCA = 180^{\circ}

∠ PCA = 30^{\circ}

Now,

∠ APC = ∠ APB + ∠ BPC

∠ APC = 30^{\circ} + 30^{\circ}

∠ APC = 60^{\circ}

Also, in

△ PAC

90^{\circ} + 60^{\circ} + ∠ PCA = 180^{\circ}

∠ PCA = 30^{\circ}

This is the angle of depression of point C from P.
Correct option is 3.

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