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From the following set-up, calculate moles of the gas present in the container of volume 24.63 litre at 600 K if the level of mercury in the open tube of the manometer is 36 cm higher.
[Given : Atmospheric pressure =78 cm of mercury]

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3 moles

0.73 moles

1 moles

1.5 moles

answer is B.

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Detailed Solution

$\begin{array}{l} P = 78 + 36 = 114 cm of Hg \end{array}$

$n = \frac{114}{78} \times \frac{24 .63}{0 .0821} \times \frac{1}{600} n = 0 .73 moles$

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