Q.

From the following V-T diagram we can conclude 

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a

P1>P2

b

P1<P2

c

P1=P2

d

P1=2P2

answer is C.

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Detailed Solution

In case of given graph, V and T are related as V = aT + b, where a and b are constants. 
From ideal gas equation,  PV=μRT
We find  P=μRTaT+b=μRa+b/T
Since T2>T1, therefore P2>P1.

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