From the following V-T diagram we can conclude 

In case of given graph, V and T are related as V = aT + b, where a and b are constants. 
From ideal gas equation,  $\mathrm{PV}=\mu \mathrm{RT}$
We find  $\mathrm{P}=\frac{\mathrm{\mu RT}}{\mathrm{aT}+b}=\frac{\mathrm{\mu R}}{\mathrm{a}+\left(\mathrm{b}/\mathrm{T}\right)}$
Since ${\mathrm{T}}_2>{\mathrm{T}}_1$, therefore ${\mathrm{P}}_2>{\mathrm{P}}_1.$