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From the given diagram , $∠ D C E =$

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$120^{o}$

$140^{o}$

$70^{o}$

$130^{o}$

answer is C.

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Detailed Solution

$\begin{array}{l} ∠ A + ∠ B + ∠ C + ∠ D = 360 ° \\ = 70 ° + 60 ° + 120 ° + ∠ D C B = 360 ° \\ ∠ D C B = 110 ° \\ ∠ D C B + ∠ D C E = 180 ° \\ ∠ D C E = 70 ° \end{array}$

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