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Q.

From the magnetic behaviour of NiCl42 (paramagnetic) and Ni(CO)4 (diamagnetic), choose the correct geometry and oxidation state.

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a

NiCl42: NiII, tetrahedral
Ni(CO)4: Ni(0), tetrahedral

b

NiCl42: NiII, tetrahedral
Ni(CO)4: NiII, square planar

c

NiCl42: Ni(0), tetrahedral
Ni(CO)4: Ni(0), square planar

d

NiCl42: NiII , square planar
Ni(CO)4: Ni(0), square planar

answer is B.

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Detailed Solution

NiCl42
Ni+2[Ar]3d84s0sp3 Tetrahedral
Number of unpaired electron =2 paramagentic
Ni(CO)4,
Ni(0)[Ar]3d104s0(After rearrangement)
No unpaired electron
sp3, Tetrahedral, Diamagnetic

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