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Fundamental frequency of a sonometer wire is n, if the tension is made 3 times and length and diameter are also increased 3 times, what is the new frequency ?

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$\sqrt{3} n$

$\frac{n}{\sqrt{3}}$

$\frac{n}{3 \sqrt{3}}$

answer is A.

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Detailed Solution

$f = \frac{1}{2 l} \sqrt{\frac{T}{μ}} = \frac{1}{2 l} \sqrt{\frac{T}{π r^{2} d}} α \frac{\sqrt{T}}{l r}$

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