Q.

Fundamental frequency of a stretched sonometer wire is  f0. When its tension is increased by 96% and length decreased by 35%, its fundamental frequency becomes  η1f0. When its tension is decreased by 36% and its length is increased by 30%, its fundamental frequency becomes  η2f0. The value of  η1η2 is found to be  7n. Find n.

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answer is 2.

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Detailed Solution

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f0=12LTμ          . (i)

f=12(LΔL)T+ΔTμ=nf0     . (ii)

So,  η1=LL+ΔLT+ΔTT=T+ΔTT1+ΔTL=1+0.9610.35=1.960.65=1.40.65

η2=10.361+0.30=0.641.3=0.81.3      η1η2=1.40.65×1.30.8=3.5

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