Fundamental frequency of an open pipe of length 0.5 m is equal to the frequency of the first overtone of a closed pipe of length l. The value of l_c is (m)

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0.75

1.5

answer is B.

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Detailed Solution

Fundamental frequency of open pipe = first overtone of closed pipe $\Rightarrow \frac{v}{2 l_{0}} = \frac{3 v}{4 l_{c}} \Rightarrow l_{c} = \frac{3 \times 2 \times 0 .5}{4} = 0 .75 m$

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