Fusion of chromite ore $(F e C r_{2} O_{4})$ with $N a_{2} C O_{3}$ in the presence of $O_{2}$ gives X which on acidification with conc. $H_{2} S O_{4}$ gives Y. Both X and Y contain chromium ion. Correct statement(s) is/are:

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Both X and Y are colourful compound and colour of these compounds is due to ligand to metal charge transfer.

Both X and Y are paramagnetic in nature.

Acidified solution of Y can convert $S n^{2 +}$ ion into $S n^{4 +}$ ion.

Both X and Y have Question Image bond

answer is C, A.

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Detailed Solution

$F e C r_{2} O_{4} + N a_{2} C O_{3} + O_{2} \to \underset{X}{N a_{2} C r O_{4}} + F e_{2} O_{3} + C O_{2} N a_{2} C r O_{4} + H^{+} \to \underset{' Y'}{N a_{2} C r_{2} O_{7}} + H_{2} O$

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