Fusion of chromite ore with sodium carbonate in excess of air gives a compound (X) (yellow solution) X when treated with sulphuric acid gives :

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${Na}_{2} {Cr}_{2} O_{7} \cdot 5 H_{2} O$

${Na}_{2} {Cr}_{2} O_{7} \cdot 10 H_{2} O$

${Na}_{2} {Cr}_{2} O_{7} \cdot 2 H_{2} O$

${Na}_{2} {Cr}_{2} O_{7}$

answer is D.

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Detailed Solution

$\begin{array}{l} 4 {FeCr}_{2} O_{4} + 8 {Na}_{2} {CO}_{3} + 7 O_{2} \to 8 {Na}_{2} {CrO}_{4} + 2 {Fe}_{2} O_{3}^{+} \\ + 8 {CO}_{2} \\ 2 {Na}_{2} {CrO}_{4} + 2 H^{+} \to {Na}_{2} {Cr}_{2} O_{7} + 2 {Na}^{+} + H_{2} O \end{array}$

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