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Q.

f(x)'f'(x)g(x)f(x).g(x)logg(x)logf(x)dx=

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a

2log fx+log gx+c

b

12loggxfx2+c

c

loggxfx2+c

d

log fx-log gx+c

answer is A.

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Detailed Solution

f(x)'f'(x)g(x)f(x).g(x)logg(x)logf(x)dx

=f(x).g'xg'(x)f'(x)f(x)2gxfxloggxfxdx =dgxfx1gx×loggxfx =log tt.dt   where gxfx =log t22+C =12log gxfx2+C

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∫f(x)'−f'(x)g(x)f(x).g(x)logg(x)−logf(x)dx=