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Q.

f(x)=sinax2x2,x034+14a,x=0   for what values  of a, f(x) is continuous at x = 0

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a

14,1

b

14,1

c

1,14

d

1,14

answer is C.

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Detailed Solution

 x0Ltf(x)=f(0) 

 x0Ltsinax2x2=34+14a

 x0Ltsinax2ax2×a=34+14a   a=34+14a

4a2-3a-1=0a=1/4,1

 

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