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Q.

f(x)=[x2][x]2 , then (where [.] denotes greatest integer function)

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a

f is not continuous x = 0 and x = 1

b

f is continuous at   x = 0 but not at  x = 1

c

f is not continuous at  x = 0 but continuous at  x = 1

d

f is continuous at x = 0 and  x = 1

answer is C.

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Detailed Solution

f(0)=0(1)2=1andf(0)=0.  Hence f  is not continuous at x=0 

(1)f(1)=00=0 , f(1+)=11=0  f(1)=0 and  Thus f  is continuous at x=1 

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