$f\left(x\right)=x^2-2x+4thenthesetofvaluesofxsatisfyingf(x-1)=f(x+1)is$

$\begin{array}{l}f\left(x\right)=x^2-2x+4\\ Letf(x-1)=f(x+1)\\ \Rightarrow {(x-1)}^2-2(x-1)+4={(x+1)}^2-2(x+1)+4\\ \Rightarrow x^2+1-2x-2x+2+4=x^2+1+2x-2x-2+4\\ \Rightarrow -4x=-4\\ \Rightarrow x=1\end{array}$