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$f x = x 2 − 4 x 3 − 6 x 2 + 11 x − 6 + x 1 + x$ , then the set of points at which the function $f x$ is not differentiable is

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An Intiative by Sri Chaitanya

− 2, 2, 1, 3

− 2, 0, 3

− 2, 2, 0

1, 3

answer is D.

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Detailed Solution

$x 1 + | x |$ is always differentiable Question Image Also $(x - 2) (x + 2) |(x - 1) (x - 2) (x - 3)|$
is not differentiable at x = 1, 3

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