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Q.

f(x)ϕ(x)f(x)ϕ(x)f(x)ϕ(x){logϕ(x)logf(x)}dx=

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a

logϕ(x)f(x)+k

b

ϕ(x)f(x)logϕ(x)f(x)+k

c

logϕ(x)f(x)2+k

d

12logϕ(x)f(x)2+k

answer is B.

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Detailed Solution

f(x)ϕ(x)f(x)ϕ(x)f(x)ϕ(x){logϕ(x)logf(x)}dx=logϕ(x)f(x)f(x)ϕ(x)f(x)ϕ(x)f(x)ϕ(x)dxput  t= logϕ(x)f(x) then dt=f(x)ϕ(x)f(x)ϕ(x)f(x)ϕ(x)dx    G.I= t dt =t22+k               = logϕ(x)f(x)22+K 

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∫f(x)⋅ϕ′(x)−f′(x)⋅ϕ(x)f(x)⋅ϕ(x){log⁡ϕ(x)−log⁡f(x)}dx=