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${ΔG}^{0}$ for reaction, ${Cu}^{2 +} + Fe \to {Fe}^{2 +} + Cu$ is
[Given: $E_{C u^{2 +} / C u}^{0} = + 0.34 V$ and $E_{F e^{2 +} / F e}^{0} = - 0.44 V$ ]

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11.44 KJ

180.8 KJ

-150.5 KJ

28.5 KJ

answer is C.

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Detailed Solution

$E_{c e l l}^{0} = E_{C u^{2 +} / C u}^{0} - E_{F e^{2 +} / F e}^{0}$
$= 0.34 - (- 0.44) = 0.78$
$Δ G^{0} = - n F E_{c e l l}^{0}$
$= - 2 x 96500 x 0.78$
$= - 150540 J$
$= - 150.5 k J$

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