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$Δ G^{0}$ vs T plot in Ellingham diagram having downward slope is related with which of the following reaction

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$C_{(s)} + \frac{1}{2} O_{2 (g)} \to C O_{(g)}$

$M g_{(s)} + \frac{1}{2} O_{2 (g)} \to M g O_{(s)}$

$2 A g_{(s)} + \frac{1}{2} O_{2 (g)} \to A g_{2} O_{(s)}$

$C O_{(g)} + \frac{1}{2} O_{2 (g)} \to C O_{2 (s)}$

answer is A.

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Detailed Solution

$C + \frac{1}{2} O_{2} \to C O$

In the above reaction, oxygen gas is used with carbon and forms CO gas. Half moles of gas consumed and forms one mole of gas, this means that entropy increases; hence slope behavior is downward.

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