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Q.

Galileo writes that for angle of projection of a projectile at angle (450 - θ) and (450 + θ), the horizontal ranges described by the projectile are in the ratio of (if θ  450)

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a

2 : 1

b

2 : 3

c

1 : 2

d

1 : 1

answer is C.

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Detailed Solution

For angle (450 - θ), R=u2sin90°-2θg=u2cos2θg

For angle (450 + θ), R=u2sin90°+2θg=u2cos2θg

Thus, ratio becomes 1 : 1.

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Galileo writes that for angle of projection of a projectile at angle (450 - θ) and (450 + θ), the horizontal ranges described by the projectile are in the ratio of (if θ ≤ 450)